X 2 2x 4 0

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X 2 2x 4 0

This site is best viewed with Javascript. If you are unable to turn on Javascript, please click here. Observation : No two such factors can be found!! Conclusion : Trinomial can not be factored. Our parabola opens down and accordingly has a highest point AKA absolute maximum. We know this even before plotting "y" because the coefficient of the first term, -1 , is negative smaller than zero. Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x -intercepts roots or solutions of the parabola. That is, if the parabola has indeed two real solutions. Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.

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This site is best viewed with Javascript. If you are unable to turn on Javascript, please click here. The middle term is, -2x its coefficient is Observation : No two such factors can be found!! Conclusion : Trinomial can not be factored. Our parabola opens up and accordingly has a lowest point AKA absolute minimum. We know this even before plotting "y" because the coefficient of the first term, 1 , is positive greater than zero. Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x -intercepts roots or solutions of the parabola.

X 2 2x 4 0

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